**Frank Learning Maths Class 8 Chapter 2 Exponents Exercise 2.2 Solutions**

This post is created to help all the CBSE Class 8 students for the Solutions of Frank Learning Maths Class 8 Mathematics Book, Chapter 2 Exponents Exercise 2.2. Here students can easily find step by step solutions of all the problems for Exponents Exercise 2.2. Exercise wise proper solutions for every problems. All the problem are solved with easily understandable methods so that all the students can understand easily.

**Chapter 2 – Exponents**

**Exponents – Exercise 2.2 all Questions Solution**

**(1) Express the following numbers in standard from
**

**Solution : **

**(a)** 2, 43, 00, 00, 00, 000 in standard form,

= 243 × 10^{9
}

= 2.43 × 10^{11}

**(b)** 89, 00, 00, 00, 000 in standard,

= 8.9 × 10^{10}

**(c)** 16, 70, 000 in standard,

= 1.67 × 10^{6}

**(d)** 0.0000000029 in standard,

= 2.9 × 10^{-9}

**(e)** 0.00000000007 in standard,

= 7 × 10^{-10}

**(2) Express the following in the usual form
**

**Solution : **

**(a)** 1.732 × 10^8

In usual form = 173200000

**(b)** 9.7137 × 10^13

In usual form = 97137000000000

**(c)** 4.01853 × 10^7

In usual form = 40185300

**(d)** 1.31 × 10^-9

In usual form = 0.0000000131

**(e)** 5.3 × 10^-13

In usual form = 0.00000000000053

**(f)** 8.37 × 10^-6

In usual form = 0.0000837

**(3) Express the number which appears in each of the following statements in its standard form**

**Solution : **

**(a)** Size of a bacteria is 0.0000005 m.

In standard form = 5 × 10^-6 m

**(b)** Diameter of the write on a computer chip is 0.000003 m.

In standard form = 3 × 10^-5 m

**(c)** Speed of light is 300, 000, 000 m/s.

In standard form = 3 × 10^8 m/s

**(d)** The distance of the moon from the earth is 384, 460, 000 m (approx.)

In standard form = 3.8446 × 10^8 (approx.)

**(e)** Size of a plant cell is 0.000 000 012 75 km.

In standard form = 1.275 × 10^-10 km.

**(f)** Distance of the sun from the earth is 149, 600, 000 km.

In standard form = 1.496 × 10^8 km.

**Question no – (4) **

**Solution : **

As per the given question,

The size of an animal cell is = 0.0000068 m

The size of a plant cell is = 0.000015 m

**∴** 0.000015/0.0000068

= 15/68 × 10^{-10
}

= 150/68

= 75 : 34

Hence, the ratio of the size of the plant cell to that of the animal cell will be 75 : 34

**Question no – (5) **

**Solution : **

According to the question,

Diameter of the sun = 1.4 × 10^{9} m

Diameter of the earth = 1.275 × 10^{7}m

**∴** 1.4 × 10^{9}/1.275 × 10^{7
}

= 14 × 10/1275 × 10^{4
}

= 14 × 10^{4}/1275

= 5600 : 51

Therefore, the ratios of their diameters will be 5600 : 51

**Question no – (6) **

**Solution : **

Total pages,

= 500 × 7

= 3500 pages

Thickness,

= 0.000075m

= 75 × 10^{-4} m.

∴ Thickness of the stack,

= 3500 × 75 × 10^{-4 }m

= 35 × 75 × 10^{-2} m

= 2625 × 10^{-2} m

= 26.25 m

Therefore, the total thickness of the stack will be 26.25 m.