ICSE Number Line Class 6 Chapter 18 Data Handling Exercise 18E Solutions

ICSE Number Line Class 6 Chapter 18 Data Handling Exercise 18E Solutions

This post is created to help all the ICSE Class 6 students for the Solutions of Number Line Class 6 Mathematics Book, Chapter 18 Data Handling Exercise 18E. Here students can easily find step by step solutions of all the problems for Data Handling Exercise 18E. Here students all find exercise wise proper solutions for every problems. Here all the problem are solved with easy to understand methods so that all students can understand easily.

Chapter 18 – Data Handling

Data Handling – Exercise 18E all Questions Solution

Question no – (1)

Solution :

Arranging in ascending order
82, 85, 85, 87, 87, 87, 90, 90, 90
No of observation = 9
(9 + 1/2)th position
Median = 10/2th position
= 5^th position
= 87

Question no – (2)

Solution :

In ascending order
8, 10, 10, 12, 12, 15
No of observation = 6 (even)
So,
Median = x/2th position + (x/2 + 1) position/2
= 6/2 position + (6/2 + 1) position/2
= 3^rd position + 4^th position/2
= 10 + 12/2
= 11

Question no – (3)

Solution :

In ascending order
5000, 8000, 8000, 9000, 9000, 10000, 10000, 10000, 50000
No of observation = 9 (odd)
So, median = (x + 1/2)th position
= 9 + 1/2th position
= 5^th position
= Rs 9000

Question no – (4)

Solution :

Mean = 7 + 6 + 5 + 6 + 5 + 7 + 6 + 5/8
= 47/8
= 5.875
In ascending order
5, 5, 5, 6, 6, 6, 7, 7
No of observation = 8
Median = (x/2th position + (x/2 + 1)th position)/2
= (4^th position + (4 + 1)th position)/2
= 4^th position + 5^th position/2
= 6 + 6/2
= 6
No of mean and median are not same.

Multiple Choice Question

(i) On which day were the maximum number of parcels delivered?

Solution :

Maximum number of parcels delivered – (d) Thursday

(ii) On which day were the minimum number of parcels delivered?

Solution :

Minimum number of parcels delivered – (a) Saturday

(iii) How many more parcels were delivered on Tuesday than on Monday?

Solution :

Difference between Tuesday and Monday per parcels
= (9 – 7) × 10
= 2 × 10
= 20
So, The correct option is – (a) 20

(iv) What was the total number of parcels delivered over the whole week?

Solution :

Total parcels delivered over a week
(5 + 7 + 4 + 9 + 6 + 3) × 10
= 34 × 10
= 340
So, The correct option is – (c) 340